Hi Travis,
Travis Oliphant wrote:
> Ryan Gutenkunst wrote:
>> I notice that numpy_array.item() will give me the first element as a
>> normal scalar. Would it be possible for numpy_array.item(N) to return
>> the Nth element of the array as a normal scalar?
>>
> Now this is an interesting idea. It would allow you to by-pass the
> slow-indexing as well as the array scalar computation should you desire
> it. I like it and am going to add it unless there are convincing
> objections.
>
> -Travis
Thanks for the quick response, but either there's a bug, or I'm using
things wrong. It appears to work to work in the N-D case, but not 1-D. I
looked at the change you made, but my grasp of the C-API is too weak to
isolate the problem.
>>> import numpy
>>> numpy.__version__
'1.0rc1.dev3154'
>>> a = numpy.array([[1.0, 2.0], [3.0, 4.0]])
>>> a.item(1,1)
4.0
>>> a = numpy.array([1.0, 2.0])
>>> a.item(0)
1.0
>>> a.item(1)
1.7765824089018436e-307
>>> a.item((1,))
1.7765824089018436e-307
Thanks for your help,
Ryan
--
Ryan Gutenkunst |
Cornell LASSP | "It is not the mountain
| we conquer but ourselves."
Clark 535 / (607)227-7914 | -- Sir Edmund Hillary
AIM: JepettoRNG |
http://www.physics.cornell.edu/~rgutenkunst/
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