Thanks Bill. Thats what I was hoping for, but I get >>> a array([0, 0]) >>> b array([0, 1, 0, 1, 0]) >>> c array([1, 1, 1, 1, 1]) >>> a[b]+=c Traceback (most recent call last): File "<stdin>", line 1, in ? IndexError: invalid index
whereas i would like to get array([3, 2]) On 10/8/06, Bill Baxter <[EMAIL PROTECTED]> wrote: > Yes, that'd be > a[b] += c > > On 10/8/06, Daniel Mahler <[EMAIL PROTECTED]> wrote: > > Is there a 'loop free' way to do this in Numeric > > > > for i in arange(l): > > a[b[i]]+=c[i] > > > > where l == len(b) == len(c) > > > > thanks > > Daniel > > ------------------------------------------------------------------------- > Take Surveys. Earn Cash. Influence the Future of IT > Join SourceForge.net's Techsay panel and you'll get the chance to share your > opinions on IT & business topics through brief surveys -- and earn cash > http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/numpy-discussion > ------------------------------------------------------------------------- Take Surveys. Earn Cash. Influence the Future of IT Join SourceForge.net's Techsay panel and you'll get the chance to share your opinions on IT & business topics through brief surveys -- and earn cash http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
