On 10/9/06, Tim Hochberg <[EMAIL PROTECTED]> wrote:
<snip>
Is this not the same things as numpy.multiply.outer(a, b)? (as opposed
to outer(a, b), which appears to pretend that everything is a vector --
I'm not sure what the point of that is).

Hmmm, yes, multiply.outer does do that. I thought that outer was short for multiply.outer and that the behaviour had changed. So the question is why outer does what it does.

Chuck

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