On 10/17/06, Travis Oliphant <[EMAIL PROTECTED]> wrote:
Charles R Harris wrote:
>
>
> On 10/17/06, *Lisandro Dalcin* <[EMAIL PROTECTED]
> <mailto:[EMAIL PROTECTED]>> wrote:
>
>     I was surprised by this
>
>     In [14]: array([[1,2,3],[4,5,6]]).reshape((3,2),order='F')
>     Out[14]:
>     array([[1, 5],
>            [4, 3],
>            [2, 6]])
>
>
> This one still looks wrong.

Why does this look wrong.  What do you want it to be?  Perhaps you are
thinking about the input array as C-order and the output array as
Fortran order.   That's not what reshape does.   The order argument
specifies how you think about both the input and output.

Thus, reshape does the equivalent of a Fortran ravel to [1,4,2,5,3,6]
and then a Fortran-order based fill of an empty (3,2) array:  giving you
the result.

Why a Fortran ravel? I am thinking of it as preserving the memory layout, just messing with how it is addressed.

Chuck

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