On 10/19/06, David Huard <[EMAIL PROTECTED]> wrote:
In [8]: a.sum(1)[:,newaxis,:].shape
Out[8]: (10, 1, 10)
Don't know if this is as universal as you want, but it works for this. Robert's answer is more general.
Chuck
Hi,
Is there an elegant way to reduce an array but conserve the reduced dimension ?
Currently,
>>> a = random.random((10,10,10))
>>> a.sum(1).shape
(10,10)
but i'd like to keep (10,1,10) so I can do a/a.sum(1) directly.
In [8]: a.sum(1)[:,newaxis,:].shape
Out[8]: (10, 1, 10)
Don't know if this is as universal as you want, but it works for this. Robert's answer is more general.
Chuck
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