Maybe I'm missing something. This seems fine to me: >>> bool(np.array([])) False
But I would have expected these to raise ValueErrors recommending any() and all(): >>> bool(np.array([1])) True >>> bool(np.array([0])) False On Fri, Aug 18, 2017 at 3:00 PM, Stephan Hoyer <sho...@gmail.com> wrote: > I agree, this behavior seems actively harmful. Let's fix it. > > On Fri, Aug 18, 2017 at 2:45 PM, Michael Lamparski < > diagonaldev...@gmail.com> wrote: > >> Greetings, all. I am troubled. >> >> The TL;DR is that `bool(array([])) is False` is misleading, dangerous, >> and unnecessary. Let's begin with some examples: >> >> >>> bool(np.array(1)) >> True >> >>> bool(np.array(0)) >> False >> >>> bool(np.array([0, 1])) >> ValueError: The truth value of an array with more than one element is >> ambiguous. Use a.any() or a.all() >> >>> bool(np.array([1])) >> True >> >>> bool(np.array([0])) >> False >> >>> bool(np.array([])) >> False >> >> One of these things is not like the other. >> >> The first three results embody a design that is consistent with some of >> the most fundamental design choices in numpy, such as the choice to have >> comparison operators like `==` work elementwise. And it is the only such >> design I can think of that is consistent in all edge cases. (see footnote 1) >> >> The next two examples (involving arrays of shape (1,)) are a >> straightforward extension of the design to arrays that are isomorphic to >> scalars. I can't say I recall ever finding a use for this feature... but >> it seems fairly harmless. >> >> So how about that last example, with array([])? Well... it's /kind of/ >> like how other python containers work, right? Falseness is emptiness (see >> footnote 2)... Except that this is actually *a complete lie*, due to /all >> of the other examples above/! >> >> Here's what I would like to see: >> >> >>> bool(np.array([])) >> ValueError: The truth value of a non-scalar array is ambiguous. Use >> a.any() or a.all() >> >> Why do I care? Well, I myself wasted an hour barking up the wrong tree >> while debugging some code when it turned out that I was mistakenly using >> truthiness to identify empty arrays. It just so happened that the arrays >> always contained 1 or 0 elements, so it /appeared/ to work except in the >> rare case of array([0]) where things suddenly exploded. >> >> I posit that there is no usage of the fact that `bool(array([])) is >> False` in any real-world code which is not accompanied by a horrible bug >> writhing in hiding just beneath the surface. For this reason, I wish to see >> this behavior *abolished*. >> >> Thank you. >> -Michael >> >> Footnotes: >> 1: Every now and then, I wish that `ndarray.__{bool,nonzero}__` would >> just implicitly do `all()`, which would make `if a == b:` work like it does >> for virtually every other reasonably-designed type in existence. But then >> I recall that, if this were done, then the behavior of `if a != b:` would >> stand out like a sore thumb instead. Truly, punting on 'any/all' was the >> right choice. >> >> 2: np.array([[[[]]]]) is also False, which makes this an interesting sort >> of n-dimensional emptiness test; but if that's really what you're looking >> for, you can achieve this much more safely with `np.all(x.shape)` or >> `bool(x.flat)` >> >> _______________________________________________ >> NumPy-Discussion mailing list >> NumPy-Discussion@python.org >> https://mail.python.org/mailman/listinfo/numpy-discussion >> >> > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@python.org > https://mail.python.org/mailman/listinfo/numpy-discussion > >
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