I think you are saying that this current behavior of `choose` should
be considered a bug. I hope not, because as illustrated, it is useful.
How would you propose to efficiently do the same substitutions?
On 4/17/2021 4:27 PM, Kevin Sheppard wrote:
2. I would describe this a a bug. I think sequences are converted to arrays and in this case the conversion is not returning a 2 element object array but
expanding and then concatenation.
On Sat, Apr 17, 2021, 18:56 Alan G. Isaac <alan.is...@gmail.com
<mailto:alan.is...@gmail.com>> wrote:
2. Separately, mypy is unhappy with my 2nd argument to `choose`:
Argument 2 to "choose" has incompatible type "Tuple[int, Sequence[float]]";
expected "Union[Union[int, float, complex, str, bytes, generic],
Sequence[Union[int, float, complex, str, bytes, generic]],
Sequence[Sequence[Any]],_SupportsArray]"
However, `choose` is happy to have e.g. `choices=(0,seq)` (and I hope it
will remain so!).
E.g.,
a = a = (0,1,1,0,0,0,1,1) #binary array
np.choose(a, (0,range(8)) #array([0, 1, 2, 0, 0, 0, 6, 7])
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