> You could use `dis.dis` to compare the two expressions and see that they
> compile to the same bytecode.
Do you mean the following:
In [1]: import numpy as np
In [2]: from dis import dis
In [7]: dis('bool')
1 0 LOAD_NAME 0 (bool)
2 RETURN_VALUE
In [8]: dis('(bool)')
1 0 LOAD_NAME 0 (bool)
2 RETURN_VALUE
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