After blinking and rubbing my eyes, I finally see what is meant by all of this. I see now that the difference is that `cumsum0()` would return a result that essentially have 0 be prepended to what would normally be the result from `cumsum()`. From the description, I thought the "problem" was that the summation starts from 1. Personally, I never really thought of cumsum() as starting from index 1, so I didn't understand the problem as stated.
So, I think some workshopping of the description is in order. On Fri, Aug 11, 2023 at 1:53 PM Robert Kern <[email protected]> wrote: > On Fri, Aug 11, 2023 at 1:47 PM Benjamin Root <[email protected]> > wrote: > >> I'm really confused. Summing from zero should be what cumsum() does now. >> >> ``` >> >>> np.__version__ >> '1.22.4' >> >>> np.cumsum([[1, 2, 3], [4, 5, 6]]) >> array([ 1, 3, 6, 10, 15, 21]) >> ``` >> which matches your example in the cumsum0() documentation. Did something >> change in a recent release? >> > > That's not what's in his example. > > -- > Robert Kern > _______________________________________________ > NumPy-Discussion mailing list -- [email protected] > To unsubscribe send an email to [email protected] > https://mail.python.org/mailman3/lists/numpy-discussion.python.org/ > Member address: [email protected] >
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