Giorgio Luciano wrote:
> Today I've also posted a question to scipy groups because I've thought
> I've found a solution but
>
> this work good
>
> bar(N, b1[:,0], width, color='r', yerr=binterv)
> ############
> s3=find(sig1[:,arange(ini,c)]<=0.001)
> b1=b.flatten()
> #if s3!=[]:
> for i3 in arange(len(s3)):
> text(s3[i3], b1[s3[i3]+ini],'***')
> s2=find(logical_and(sig1[:,arange(ini,c)]>0.001,sig1[:,arange(ini,c)]<=0.01))
> for i2 in arange(len(s2)):
> text(s2[i2], b1[s2[i2]+ini],'**')
> s1=find(logical_and(sig1[:,arange(ini,c)]>0.01,sig1[:,arange(ini,c)]<=0.05))
> for i1 in arange(len(s1)):
> text(s1[i1], b1[s1[i1]+ini],'*')
> title('Plot of the coefficients of the model')
>
> and when i uncomment the ifs3!=[] part it does not...
> so in this case I've solve the problem.. but is there an equivalent for
> isempty matlab command in numpy ?
Use (len(s3) != 0) instead of (s3 != []).
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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