Hi Eric, Here are ways of doing this. starting with import numpy as N
On 12/28/06, Eric Emsellem <[EMAIL PROTECTED]> wrote:
### Increasing order in x, and x1 <= x2 : x = arange(0.,1.,0.1) x1 = 0.1 x2 = 0.55 ### the output I would like is simply: array([ 0.1, 0.2, 0.3, 0.4, 0.5])
How about this? x=N.arange(0.,1.,0.1) x[ (x>=0.1) & (x<=0.55) ] ### decreasing order in x, and x1 <= x2 :
x = arange(0.,-1.,-0.1) x1 = -0.55 x2 = -0.1 ### I would like is then: array([ -0.5, -0.4, -0.3, -0.2, -0.1])
x=N.arange(0.,-1.,-0.1) N.sort( x[ (x<=-0.1) & (x>=-0.55) ] ) or x[(x<=-0.1)&(x>=-0.55)][::-1] just reverses the returned array. ### decreasing order in x, and x1 >= x2 :
x = arange(0.,-1.,-0.1) x1 = -0.1 x2 = -0.55 ### I would like is then: array([ -0.1, -0.2, -0.3, -0.4, -0.5])
x=N.arange(0.,-1.,-0.1) x[ (x<=-0.1) & (x>=-0.55) ] A few comments because I'm not totally clear on what you want to do. (x<=-0.1)&(x>=-0.55) will give you a boolean array of the same length as x find((x<=-0.1)&(x>=-0.55)) will return the list of indices where the argument is true. Regards, Greg -- Linux. Because rebooting is for adding hardware.
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