On 25 Feb 2007 01:44:01 +0000, Alexander Schmolck <[EMAIL PROTECTED]>
wrote:

"Charles R Harris" <[EMAIL PROTECTED]> writes:

> > Unfortunately I don't see an easy way to use the same approach the
other
> > way
> > (matlab doesn't seem to offer much on the C level to manipulate
arrays),
> > so
> > I'd presumably need something like:
> >
> >   stuff_into_matlab_array(a.T.reshape(a.shape).copy())
> >
> > the question is how to avoid doing two copies.
> >
> > Any comments appreciated,
>
>
> The easiest way to deal with the ordering is to use the order keyword in
> numpy:
>
> In [4]: a = array([0,1,2,3]).reshape((2,2), order='F')
>
> In [5]: a
> Out[5]:
> array([[0, 2],
>        [1, 3]])
>
> You would still need to get access to something to reshape, shared
memory or
> something, but the key is that you don't have to reorder the elements,
you
> just need the correct strides and offsets to address the elements in
Fortran
> order. I have no idea if this works in numeric.

It doesn't work in Numeric, but that isn't much of any issue because I
think
it ought to be pretty much equivalent by transposing and reshaping.
However
the problem is that I *do* need to reorder the elements for numpy->matlab
and
I'm not sure how to best do this (without unnecessary copying and
temporary
numpy array creation but using numpy functionality if possible).


I don't see any way to get around a copy, but you can make numpy do the
work. For example:

In [12]: a = array([[0,1],[2,3]])

In [13]: b = array(a, order='f')

In [14]: a.flags
Out[14]:
 C_CONTIGUOUS : True
 F_CONTIGUOUS : False
 OWNDATA : True
 WRITEABLE : True
 ALIGNED : True
 UPDATEIFCOPY : False

In [15]: b.flags
Out[15]:
 C_CONTIGUOUS : False
 F_CONTIGUOUS : True
 OWNDATA : True
 WRITEABLE : True
 ALIGNED : True
 UPDATEIFCOPY : False

F_CONTIGUOUS is what you want. The trick is to somehow use memory in the
construction of the reordered array that is already designated for matlab. I
don't know how to do this, but I think it might be doable. Travis is your
best bet to answer that question.

Chuck
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