No, the nth index of a Python sequence is a[n], where n starts from zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
I reverted the page to its original form and added a couple explanatory comments about zero vs one based indexing. dmitrey wrote: > now there is > MATLAB NDArray Matrix > size(a,n) a.shape[n] a.shape[n] > > but it should be > size(a,n) a.shape[n-1] a.shape[n-1] > > WBR, D. > _______________________________________________ > Numpy-discussion mailing list > [email protected] > http://projects.scipy.org/mailman/listinfo/numpy-discussion _______________________________________________ Numpy-discussion mailing list [email protected] http://projects.scipy.org/mailman/listinfo/numpy-discussion
