A late entry, but here's something that gets you an array of counts for each unique integer:
>>> data = numpy.array([9, 6, 9, 6, 7, 9, 9, 10, 7, 9, 9, 6, 7, 9, 8, 8, 11, 9, 6, 7, 10, 9, 7, 9, 7, 8, 9, 8, 7, 9]) >>> unique=numpy.unique(data) >>> unique array([ 6, 7, 8, 9, 10, 11]) >>> histo=numpy.histogram(data,unique) >>> histo (array([ 4, 7, 4, 12, 2, 1]), array([ 6, 7, 8, 9, 10, 11])) >>> So histo[0] includes the counts of each integer in data. -Mark 2007/8/7, Nils Wagner <[EMAIL PROTECTED]>: > > Hi all, > > I have a list of integer numbers. The entries can vary between 0 and 19. > How can I count the occurrence of any number. Consider > > >>> data > [9, 6, 9, 6, 7, 9, 9, 10, 7, 9, 9, 6, 7, 9, 8, 8, 11, 9, 6, 7, 10, 9, 7, > 9, 7, 8, 9, 8, 7, 9] > > > Is there a better way than using, e.g. > > >>> shape(where(array(data)==10))[1] > 2 > > > to compute the occurrence of 10 in the list which is 2 in this case ? > > Nils _______________________________________________ Numpy-discussion mailing list [email protected] http://projects.scipy.org/mailman/listinfo/numpy-discussion
