Hi all, I was just trying to write a unit test for something where I was expecting to get some NaN's in the array. However, since NaN == NaN returns false, the simple test:
assert(alltrue(a == b)) >>> a = N.array((1,2,3,N.nan)) >>> b = N.array((1,2,3,N.nan)) >>> a == b array([ True, True, True, False], dtype=bool) >>> assert(N.alltrue(a == b)) Traceback (most recent call last): File "<stdin>", line 1, in <module> AssertionError >>> So is there any way to test is two arrays are the same, when there may be a NaN or two mixed in??? With a bit of thought -- this works: >>> N.alltrue(a[~N.isnan(a)] == b[~N.isnan(b)]) True but that feels like a kludge. maybe some sort of "TheseArrays are binary equal" would be useful. -CHB -- Christopher Barker, Ph.D. Oceanographer Emergency Response Division NOAA/NOS/OR&R (206) 526-6959 voice 7600 Sand Point Way NE (206) 526-6329 fax Seattle, WA 98115 (206) 526-6317 main reception [EMAIL PROTECTED] _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
