Charles R Harris wrote: > What *should* the resize method do? It looks like > it is equivalent to assigning a shape tuple to a.shape,
No, that's what reshape does. > so why do we need it? resize() will change the SIZE of the array (number of elements), where reshape() will only change the shape, but not the number of elements. The fact that the size is changing is why it won't work if if doesn't own the data. >>> a = N.array((1,2,3)) >>> a.reshape((6,)) Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: total size of new array must be unchanged can't reshape to a shape that is a different size. >>> b = a.resize((6,)) >>> repr(b) 'None' resize changes the array in place, so it returns None, but a has been changed: >>> a array([1, 2, 3, 0, 0, 0]) Perhaps you want the function, rather than the method: >>> b = N.resize(a, (12,)) >>> b array([1, 2, 3, 0, 0, 0, 1, 2, 3, 0, 0, 0]) >>> a array([1, 2, 3, 0, 0, 0]) a hasn't been changed, b is a brand new array. -CHB Apart from that, the reshape method looks like it would serve > for most cases. > > Chuck > > > ------------------------------------------------------------------------ > > _______________________________________________ > Numpy-discussion mailing list > [email protected] > http://projects.scipy.org/mailman/listinfo/numpy-discussion -- Christopher Barker, Ph.D. Oceanographer Emergency Response Division NOAA/NOS/OR&R (206) 526-6959 voice 7600 Sand Point Way NE (206) 526-6329 fax Seattle, WA 98115 (206) 526-6317 main reception [EMAIL PROTECTED] _______________________________________________ Numpy-discussion mailing list [email protected] http://projects.scipy.org/mailman/listinfo/numpy-discussion
