My bad...I also note that I forgot to decrement the descending list in my example. Ignore....
Robert Kern wrote: > Mark.Miller wrote: >> Check how you're implementing the histogram function with respect to >> that range statement. It seems to make a difference, desirable or not. >> >> >>> import numpy >> >>> numpy.__version__ >> '1.0.4.dev3982' >> >>> A = numpy.array([1, 2, 3, 4, 5, 6, 5, 4, 5, 4, 3, 2, 1]) >> >>> (x, y) = numpy.histogram(A, range(0, 7)) >> >>> x >> array([0, 2, 2, 2, 3, 3, 1]) >> >>> y >> [0, 1, 2, 3, 4, 5, 6] >> >>> >> >>> (x, y) = numpy.histogram(A, range=(0, 7)) >> >>> x >> array([0, 2, 2, 0, 2, 3, 0, 3, 1, 0]) >> >>> y >> array([ 0. , 0.7, 1.4, 2.1, 2.8, 3.5, 4.2, 4.9, 5.6, 6.3]) > > Please check the signature of numpy.histogram(). The two aren't intended to be > the same. The range argument has nothing to do with the builtin range() > function. > >> >>> >> >>> >> >>> (x, y) = numpy.histogram(A, range(7,0)) >> >>> x >> array([], dtype=int32) >> >>> y >> [] >> >>> >> >> Note that in the last case, the histogram function isn't returning >> anything for a descending range. >> >> Also notice that you're overwriting a python function with the way >> you're assigning things.... > > No, he's not. "range" is a keyword argument to histogram(). He's using it > correctly. > _______________________________________________ Numpy-discussion mailing list [email protected] http://projects.scipy.org/mailman/listinfo/numpy-discussion
