Am Donnerstag, 08. November 2007 16:37:06 schrieb David Cournapeau:
> The problem is not F vs C storage: for element-wise operation, it does
> not matter at all; you just apply the same function
> (perform_operation) over and over on every element of the array. The
> order does not matter at all.

Yet Fortran order leads to several times slower operations, see the figures in 
my original post. :-(

> But what if you have segmented buffers, non aligned, etc... arrays ?

The code I posted should deal with it - by sorting the indices by decreasing 
stride, I simply ensure that all (source and target) segments are traversed 
in order of increasing memory addresses.  It does not affect segments or 
alignment.

> All this has to be taken care of,

Right - my "perform_operation(aprime)" step would need to apply the operation 
on every memory segment.

> and this means handling reference 
> count and other things which are always delicate to handle well...

I am not sure that I understand where refcounting comes into play here.

> Or 
> you just use the current situation, which let python handle it
> (through PyObject_Call and a callable, at a C level).

I need to look at the code to see what you mean here.  Probably, I have a 
wrong picture of where the slowness comes from (I thought that the order of 
the loops was wrong).

> > As I wrote above, I don't think this is good.  A fortran-order-contiguous
> > array is still contiguous, and not inferior in any way to C-order arrays.
> > So I actually expect copy() to return an array of unchanged order.
>
> Maybe this behaviour was kept for compatibility with numarray ? If you
> look at the docstring, it is said that copy may not return the same
> order than its input. It kind of make sense to me: C order is the
> default of many numpy operations.

That is very sad, because Fortran order is much more natural for handling 
images, where you're absolutely used to index with [x,y], and x being the 
faster-changing index in memory.

-- 
Ciao, /  /
     /--/
    /  / ANS
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