D.Hendriks (Dennis) wrote: > According to (for instance) > http://en.wikipedia.org/wiki/Weibull_distribution the Weibull > distribution has two parameters: lambda > 0 is the scale parameter > (real) and k > 0 is the shape parameter (real). However, the > numpy.random.weibull function has only a single 'a' parameter (except > for the size parameter which indicates the size of the array to fill > with values - this is NOT a parameter of the distribution itself). My > question is how this 'a' parameter translates to the Weibull > distribution as it 'normally' is and how to sample the distribution when > I have the lambda and k parameters?
lambda * numpy.random.weibull(k) -- Robert Kern "I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion