On Dienstag 11 Dezember 2007, Timothy Hochberg wrote: > > You mean one of the following? > > a.clip(min = 10, max = numpy.finfo(a.dtype).max) > > a.clip(min = 10, max = numpy.iinfo(a.dtype).max) > > No. I mean: > > numpy.maximum(a, 10) > > To correspond to the above example.
Great, thanks for the hints. That's good enough; could be pythonic to let
clip() forward calls to minimum/maximum if only one bound is given though.
I had a look at the code, but I am not used enough to the Python/C API, let
alone to numpy's internals, to *quickly* hack this.
Ciao, / / .o.
/--/ ..o
/ / ANS ooo
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