Hi, Did you try diag() ? Or are you saying a symmetric matrix ?
Matthieu 2008/3/26, Pierre GM <[EMAIL PROTECTED]>: > > All, > What's the quickest way to create a diagonal matrix ? I already have the > elements above the main diagonal. Of course, I could use loops: > >>>m=5 > >>>z = numpy.arange(m*m).reshape(m,m) > >>>for k in range(m): > >>> for j in range(k+1,m): > >>> z[j,k] = z[k,j] > But I was looking for something more efficient. > Thanks a lot in advance ! > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > -- French PhD student Website : http://matthieu-brucher.developpez.com/ Blogs : http://matt.eifelle.com and http://blog.developpez.com/?blog=92 LinkedIn : http://www.linkedin.com/in/matthieubrucher
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