On Tue, 29 Apr 2008, Gael Varoquaux apparently wrote: > x[i, :]*A*x[:, i] > I find this cleaner, because more explicit, than x[i]*A*x[:, i].
>> a. would e.g. ``x[i:i+1,:]`` > No way. So *if* ``x[0]`` is going to be 1d to fix the many anomalies that have surfaced, then you would still want ``x[0]==x[0,:]``, but to have those be 1d and have ``x[i, :]*A*x[:, i]`` work would require (oriented) "vector" objects, so you would want those. Is that a fair summary of your view? Cheers, Alan Isaac _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
