Hi guys, Just a quick note. I've been playing with NumPy again, looking at corner cases of function evaluation. I noticed this:
In [66]: numpy.sign(numpy.nan) Out[66]: 0.0 IMO, the output should be NaN, not zero. If you agree, then I'll be happy to file a bug in the NumPy tracker. Or if somebody feels like pointing me to the place where this is implemented, I can submit a patch. (I grepped through the source for "sign" to see if I could figure it out, but it occurs so frequently that it will take longer than 5 min to sort it all out.) Before I did anything, however, I thought I would solicit the opinions of other folks in the NumPy community about the proper behavior of numpy.sign(numpy.nan). Cheers, Stuart Brorson Interactive Supercomputing, inc. 135 Beaver Street | Waltham | MA | 02452 | USA http://www.interactivesupercomputing.com/ _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
