On Fri, May 16, 2008 at 11:47 AM, Stuart Brorson <[EMAIL PROTECTED]> wrote:
> Hi --
>
> Sorry to be a pest with corner cases, but I found another one.
>
> In this case, if you try to take the arccos of numpy.inf in the
> context of a complex array, you get a bogus return (IMO). Like this:
>
> In [147]: R = numpy.array([1, numpy.inf])
>
> In [148]: numpy.arccos(R)
> Warning: invalid value encountered in arccos
> Out[148]: array([ 0., NaN])
>
> In [149]: C = numpy.array([1+1j, numpy.inf])
>
> In [150]: numpy.arccos(C)
> Warning: invalid value encountered in arccos
> Out[150]: array([ 0.90455689-1.06127506j, NaN -Infj])
>
> The arccos(numpy.inf) in the context of a real array is OK, but taking
> arcocs(numpy.inf) in the context of a complex array should return
> NaN + NaNj, IMO.
>
> Thoughts?
Hmm, this works fine on OS X. This may be a problem with one of the
lower-level math functions which we defer to the platform.
In [1]: from numpy import *
In [2]: arccos(nan+nan*1j)
Out[2]: (nan+nanj)
In [3]: arccos(nan+0j)
Out[3]: (nan+nanj)
In [4]: arccos(nan)
Out[4]: nan
In [5]: arccos([1.0+0j, nan])
Out[5]: array([ 0. -0.j, NaN NaNj])
The implementations of the complex versions are in umathmodule.c.src
(for the expanded versions, see umathmodule.c after building); they
are all prefixed with "nc_". E.g. the following are calling nc_acos()
for doubles. Here is the source:
static void
nc_acos(cdouble *x, cdouble *r)
{
nc_prod(x,x,r);
nc_diff(&nc_1, r, r);
nc_sqrt(r, r);
nc_prodi(r, r);
nc_sum(x, r, r);
nc_log(r, r);
nc_prodi(r, r);
nc_neg(r, r);
return;
/* return nc_neg(nc_prodi(nc_log(nc_sum(x,nc_prod(nc_i,
nc_sqrt(nc_diff(nc_1,nc_prod(x,x))))))));
*/
}
I suspect the problem comes from the nc_log() which calls your
platform's atan2() for the imaginary part of the result.
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless
enigma that is made terrible by our own mad attempt to interpret it as
though it had an underlying truth."
-- Umberto Eco
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