Thanks Chuck, but I wasn't quit clear with my question.
You answered exactly according to what I asked, but I failed to mention needing
the dot product instead of just the product.
So,
v dot A = v'
v'[0] = v[0]*A[0] + v[1]*A[1] + v[2]*A[2]
v'[1] = v[0]*A[3] + v[1]*A[4] + v[2]*A[5]
v'[2] = v[0]*A[6] + v[1]*A[7] + v[2]*A[8]
-M
Date: Wed, 9 Jul 2008 13:26:01 -0600From: [EMAIL PROTECTED]: [EMAIL PROTECTED]:
Re: [Numpy-discussion] Multiplying every 3 elements by a vector?
On Wed, Jul 9, 2008 at 1:16 PM, Marlin Rowley <[EMAIL PROTECTED]> wrote:
All: I'm trying to take a constant vector: v = (0.122169, 0.61516, 0.262671)
and multiply those values by every 3 components in an array of length N: A =
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ....] So what I want is:
v[0]*A[0]v[1]*A[1]v[2]*A[2]v[0]*A[3]v[1]*A[4]v[2]*A[5]v[0]*A[6] ... How do I do
this with one command in numPy?
If the length of A is divisible by 3:A.reshape((-1,3))*vYou might want to
reshape the result to 1-D.Chuck
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