2008/9/25 Peter Saffrey <[EMAIL PROTECTED]>: > I've bodged my way through my median problems (see previous postings). Now I > need to take a z-score of an array that might contain nans. At the moment, if > the array, which is 7000 elements, contains 1 nan or more, all the results > come > out as nan. > > My other problem is that my array is indexed from somewhere else - position 0 > holds the value for a particular id, position 1 holds the value for a > particular > id and so on, so if I remove the nans, all the indices are messed up. Can > anybody suggest a sensible fix for this problem? > > I know I should really be using masked arrays, but I can't seem to find a > masked-array version of zs. Is there one?
Just keep an array of indices: c = ~np.isnan(A) Aclean = A[c] indices = np.arange(len(A))[c] Then the original index of Aclean[i] is indices[i]. Anne _______________________________________________ Numpy-discussion mailing list [email protected] http://projects.scipy.org/mailman/listinfo/numpy-discussion
