numpy 1.1.0 (from /usr/lib/python2.4/site-packages/numpy/version.py) Numeric 24.2 (from /usr/lib/python2.4/site-packages/Numeric/numeric_version.py)
I also tried with an intermediate list, but got the same result: *mylist=list(my_numpy_array) na=Numeric.array( mylist, Numeric.Float)* I don't have memory leaks if I use something like: *mylist=[0.0]*BIGNUMBER* *na=Numeric.array( mylist, Numeric.Float)* -Jose On Fri, Oct 24, 2008 at 1:54 PM, Travis E. Oliphant <[EMAIL PROTECTED]>wrote: > Jose Borreguero wrote: > > Dear numpy users, > > > > I need to pass a Numeric array to some oldie code from a numpy array. > > I decided to go like this: > > > > for i in range(BIGNUMER): > > my_numpy_array=grabArray(i) > > na=Numeric.array( my_numpy_array, Numeric.Float) > > oldie_code(na) > > > > The constructor line: > > na=Numeric.array( my_numpy_array, Numeric.Float) > > does leak memory. > > > > Is there a way to pass the Numeric array to oldie_code without the leaks? > This should work without memory leaks, but there may be a bug in NumPy > or Numeric. > > Which version of Numeric and NumPy do you have? > > -Travis > > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > -- Jose M. Borreguero Postdoctoral Associate Oak Ridge National Laboratory P.O. Box 2008, M.S. 6164 Oak Ridge, TN 37831 phone: 865-241-3071 fax: 865-576-5491 Email: [EMAIL PROTECTED]
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