Pierre GM wrote: > On Jan 30, 2009, at 1:11 PM, Raik Gruenberg wrote: > >> Mhm, I got this far. But how do I get from here to a single index >> array >> >> [ 4, 5, 6, ... 10, 0, 1, 2, 3, 11, 12, 13, 14 ] ? > > np.concatenate([np.arange(aa,bb) for (aa,bb) in zip(a,b)])
exactly! Now, the question was, is there a way to do this only using numpy functions (sum, repeat, ...), that means without any python "for" loop? Sorry about being so insistent on this one but, in my experience, eliminating those for loops makes a huge difference in terms of speed. The zip is probably also quite costly on a very large data set. Thanks! Raik > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > > -- ________________________________ Dr. Raik Gruenberg http://www.raiks.de/contact.html ________________________________ _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
