>> import numpy as np >> arr1 = np.array(['a','b','c']) >> arr2 = np.array(['d','e','f']) >> >> I would like to produce a third array that would contain >> ['ad','be','cf']. Is there an efficient way to do this? I could do >> this element by element, but I need a faster method, as I need to do >> this on arrays with several million elements. > >>>> arr1 = np.array(['a','b','c']) >>>> arr2 = np.array(['d','e','f']) >>>> arr3 = np.zeros(6, dtype='|S1') >>>> arr3[::2] = arr1 >>>> arr3[1::2] = arr2 >>>> arr3.view(dtype='|S2') > array(['ad', 'be', 'cf'], > dtype='|S2') > > Does this help?
This works wonderfully - thanks! Tom _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
