--- On Tue, 7/21/09, Christopher Barker <[email protected]> wrote:
> but now when I try to split it up:
>
> In [38]: a = a.view(dtype='S13')
>
> I get:
>
> ValueError: new type not compatible with array.
>
> Shouldn't that work?
>
> -Chris
Submit an enhancement ticket. ;-)
DG
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