I don't think np.repeat will do what I want because the order needs to
be preserved.
I have a 1x3 array that I want to repeat n times and form an nx3 array
where each row is a copy of the original array.
So far I have this:
>>> import numpy as np
>>> a = np.arange(3)
>>> b = np.asarray([a]*10)
>>> b
array([[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2],
[0, 1, 2]])
>>> b.shape
(10, 3)
the issue is that my n may be very large and I'd rather not make that
list if I don't have to.
Cheers,
Chris
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