Well, this is messy, and nearly unreadable, but it should work and is pure
python(and I think even be endian-independent).
struct.unpack('b',struct.pack('>d', X)[0])[0] >= 0
(where X is the variable you want to test)
In [54]: struct.unpack('b',struct.pack('>d',0.0)[0])[0] >= 0
Out[54]: True
In [55]: struct.unpack('b',struct.pack('>d',-0.0)[0])[0] >= 0
Out[55]: False
In [56]: struct.unpack('b',struct.pack('>d',-0.0000001)[0])[0] >= 0
Out[56]: False
In [57]: struct.unpack('b',struct.pack('>d',0.0000001)[0])[0] >= 0
Out[57]: True
In [58]: struct.unpack('b',struct.pack('>d',3999564.8763)[0])[0] >= 0
Out[58]: True
In [59]: struct.unpack('b',struct.pack('>d',-3999564.8763)[0])[0] >= 0
Out[59]: False
Hope that helps, anyway
-Joe
On Tue, Sep 29, 2009 at 12:04 PM, Christopher Barker
<chris.bar...@noaa.gov>wrote:
> Pauli Virtanen wrote:
> > Tue, 29 Sep 2009 09:53:40 -0700, Christopher Barker wrote:
> > [clip]
> >> How can I identify -0.0?
> >
> > signbit
> >
>
> perfect for numpy, but at this point I don't have a numpy dependency
> (very unusual for my code!). Anyone know a pure-python way to get it?
>
> It seems I should be able to do something like:
>
> struct.pack("d",-3.4)[0] & Something
>
> but I'm not sure what "Something" is, and it would be endian-dependent,
> wouldn't it?
>
> thanks,
> -Chris
>
>
> --
> Christopher Barker, Ph.D.
> Oceanographer
>
> Emergency Response Division
> NOAA/NOS/OR&R (206) 526-6959 voice
> 7600 Sand Point Way NE (206) 526-6329 fax
> Seattle, WA 98115 (206) 526-6317 main reception
>
> chris.bar...@noaa.gov
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