On Sat, Nov 7, 2009 at 1:51 PM, Stas K <stanc...@gmail.com> wrote: > Can I get rid of the loop in this example? And what is the fastest way > to get v in the example? > > ar = array([1,2,3]) > for a in ar: > for b in ar: > v = a**2+b**2
>>> ar[:,None]**2 + ar**2 array([[ 2, 5, 10], [ 5, 8, 13], [10, 13, 18]]) I think, for this case there is also directly a function in numpy hypot which should also work. Josef > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion > _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion