Keith Goodman wrote: > > > > Or maybe this is cleaner: > >>> [date.month==1 for date in A[:,0]] > [True, True, False, True] > > which can be used like this: > >>> idx = np.array([date.month==1 for date in A[:,0]]) >>> A[idx,:] > > array([[2010-01-01, 1], > [2010-01-02, 2], > [2010-01-05, 4]], dtype=object) > _______________________________________________ > NumPy-Discussion mailing list >
That's the keeper! Thanks for the responses. -- View this message in context: http://old.nabble.com/dates%2C-np.where-finding-months-tp27242195p27248729.html Sent from the Numpy-discussion mailing list archive at Nabble.com. _______________________________________________ NumPy-Discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
