On Wed, Feb 10, 2010 at 10:06 AM, Angus McMorland <amcm...@gmail.com> wrote:
> On 10 February 2010 11:02, Gökhan Sever <gokhanse...@gmail.com> wrote: > > Hi, > > > > Simple question: > > > > I[4]: a = np.arange(10) > > > > I[5]: b = np.array(5) > > > > I[8]: a*b.cumsum() > > O[8]: array([ 0, 5, 10, 15, 20, 25, 30, 35, 40, 45]) > > > > I[9]: np.array(a*b).cumsum() > > O[9]: array([ 0, 5, 15, 30, 50, 75, 105, 140, 180, 225]) > > > > Is there a syntactic equivalent for the I[9] --for instance instead of > using > > "list" keyword I use [ ] while creating a list. Is there a shortcut for > > np.array instead of writing np.array(a*b) explicitly? > > How about just (a*b).cumsum() ? > > Angus. > -- > AJC McMorland > Post-doctoral research fellow > Neurobiology, University of Pittsburgh > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion > Yep that's it :) I knew that it was a very simple question. What confused me is I remember somewhere not sure maybe in IPython dev I have gotten when I do: (a*b).cumsum() AttributeError: 'tuple' object has no attribute 'cumsum' error. So I was thinking ( ) is a ssugar for tuple and np.array might have something special than these. -- Gökhan
_______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
