On Tue, Jul 20, 2010 at 10:35 AM, Gael Varoquaux <gael.varoqu...@normalesup.org> wrote: > On Tue, Jul 20, 2010 at 10:24:56AM -0400, Skipper Seabold wrote: >> Will one of the stack functions do? I take it your a looks something like > >> a = [np.arange(1000), np.arange(1000), np.arange(1000)] > >> np.all(np.vstack(a) == np.concatenate([a_[None] for a_ in a])) >> # True > > Works only for 1D arrays: > > In [3]: b = np.arange(100).reshape((10, 10)) > > In [4]: a = [b, b, b] > > In [5]: np.all(np.vstack(a) == np.concatenate([a_[None] for a_ in a])) > Out[5]: False >
Hmm, yeah, wouldn't work without reshaping. np.r_[a] works, but isn't going to win you any speed contests. Skipper _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
