I get the same result on 1.4.1 On Thu, Jul 22, 2010 at 1:00 PM, Johann Hibschman < [email protected] <jhibschman%[email protected]>> wrote:
> I'm trying to understand numpy.subtract.reduce. The documentation > doesn't seem to match the behavior. The documentation claims > > For a one-dimensional array, reduce produces results equivalent to: > > r = op.identity > for i in xrange(len(A)): > r = op(r,A[i]) > return r > > However, numpy.subtract.reduce([1,2,3]) gives me 1-2-3==-4, not > 0-1-2-3==-6. > > Now, I'm on an older version (1.3.0), which might be the problem, but > which is "correct" here, the code or the docs? > > Thanks, > Johann > > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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