On Mon, Jul 26, 2010 at 5:05 PM, Skipper Seabold <jsseab...@gmail.com>wrote:
> On Mon, Jul 26, 2010 at 5:48 PM, Alan G Isaac <ais...@american.edu> wrote: > > On 7/26/2010 12:45 PM, Skipper Seabold wrote: > >> Right now np.linalg.det does not handle scalars or 1d (scalar) arrays. > > > > I don't have a real opinion on changing this, but I am curious > > to know the use case, as the current behavior seems > > Use case is just so that I can have less atleast_2d's in my code, > since checks are done in linalg.det anyway. > > > a) correct and b) to provide an error check. > > > > Isn't the determinant defined for a scalar b such that det(b) == > det([b]) == det([[b]])? > > Well, no ;) Matrices have determinants, scalars don't. Where are you running into a problem? Is something returning a scalar where a square array would be more appropriate? <snip> Chuck
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