[email protected] wrote: > On Wed, Sep 22, 2010 at 10:32 AM, Neal Becker <[email protected]> wrote: >> [email protected] wrote: >> >>> I would like to generate random numbers based on a random seed, for >>> example what numpy.random does if the seed is not specified. But I >>> would also like to print out the initial state, so I can replicate the >>> random numbers. >>> >>> Can I get a human readable or printable version of the initial state? >>> Alternatively, what's a good way to randomly generate an initial >>> state? >>> >>> I could draw an integer with randint and use it as seed. Is this the >>> best way? >>> >>> Josef >> >> import struct >> import os >> seed = struct.unpack ('I', os.urandom (4))[0] >> print seed > > >>>> os.urandom(4) > '\x02\xcf\xd5`' >>>> np.array(os.urandom(4)).view(int) > array(-452038899) >>>> import struct >>>> seed = struct.unpack ('I', os.urandom (4))[0] >>>> seed > 3650333822L >>>> np.random.seed(seed) > Traceback (most recent call last): > File "<pyshell#182>", line 1, in <module> > np.random.seed(seed) > File "mtrand.pyx", line 593, in mtrand.RandomState.seed > (numpy\random\mtrand\mtrand.c:4786) > OverflowError: long int too large to convert to int > File to fit :)
That code was used with my own random number lib based on boost _______________________________________________ NumPy-Discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
