On Wed, Sep 29, 2010 at 12:00, Pauli Virtanen <[email protected]> wrote: > Wed, 29 Sep 2010 11:15:08 -0500, Robert Kern wrote: > [clip: inplace addition with duplicates] >> Use numpy.bincount() instead. > > It might be worthwhile to add a separate helper function for this > purpose. Bincount makes a copy that could be avoided, and it is difficult > to find if you don't know about this trick.
I'm fairly certain that most of the arrays used are fairly small, as such things are reckoned. I'm not sure that in-place modification would win us much. And I'm not sure what other name for the function would make it easier to find. AFAICT, using bincount() this way is not really a "trick"; it's just the right way to do exactly this job. If anything, "x.fill(0);x[i] += 1" is the "trick". -- Robert Kern "I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco _______________________________________________ NumPy-Discussion mailing list [email protected] http://mail.scipy.org/mailman/listinfo/numpy-discussion
