On Wed, Oct 6, 2010 at 5:26 AM, Chris Withers <[email protected]>wrote:
> Hi All, > > Given an array such as: > > array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]) > > How can I find the index of a particular number in the array? > > (ie: if it was a list, I'd do [1,2,3,4].index(3)) > > cheers, > > Chris > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion > Try with numpy.where(array == value) and plain "array == value" IIRC, the first will return an array the size of the found elements and the second will return an array (or list?) of True/False. Either can be used as "index = numpy.where()" and "index = (array == value)" and then "array[index]". N
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