On Mon, Dec 27, 2010 at 10:36 AM, Mario Moura <moura.ma...@gmail.com> wrote: > Hi Folks > > a = np.zeros((4,3,5,55,5),dtype='|S8') > myLen = 4 # here I use myLen = len(something) > li = [3,2,4] # li from a list.append(something) > sl = slice(0,myLen) > tmpIndex = tuple(li) + sl + 4 # <== Here my problem > a[tmpIndex] > > # So What I want is: > fillMe = np.array(['foo','bar','hello','world']) > # But I cant contruct by hand like this > a[3,2,4,:4,4] = fillMe > a > > Again. I need construct custom slice from here > tmpIndex = tuple(li) + sl + 4 > a[tmpIndex]
First let's do it by hand: >> a = np.zeros((4,3,5,55,5),dtype='|S8') >> fillMe = np.array(['foo','bar','hello','world']) >> a[3,2,4,:4,4] = fillMe Now let's try using an index: >> b = np.zeros((4,3,5,55,5),dtype='|S8') >> myLen = 4 >> li = [3,2,4] >> sl = slice(0,myLen) Make index: >> idx = range(a.ndim) >> idx[:3] = li >> idx[3] = sl >> idx[4] = 4 >> idx = tuple(idx) Compare results: >> b[idx] = fillMe >> (a == b).all() True _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
