Robert, your answer does work: after indexing with () I can then further index into the datatype.
In [115]: a_rank_0[()][0] Out[115]: 0.0 I guess I just found the fact confusing that a_rank_1[0] and a_rank_0 compare and print equal but behave differently under indexing. More precisely if I do In [117]: b = a_rank_1[0] then In [118]: b.shape Out[118]: () and In [120]: a_rank_0 == b Out[120]: True but In [119]: b[0] Out[119]: 0.0 works but a_rank_0[0] doesn't. I thought b is a rank-0 array which it apparently is not since it can be indexed. So maybe b[0] should fail for consistency? N. _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
