On 03/16/2011 02:24 PM, Paul Anton Letnes wrote: > Hi! > > This little snippet of code tricked me (in a more convoluted form). The *= > operator does not change the datatype of the left hand side array. Is this > intentional? It did fool me and throw my results quite a bit off. I always > assumed that 'a *= b' means exactly the same as 'a = a * b' but this is > clearly not the case!
In [1]: a = np.ones(5) In [2]: b = a In [3]: c = a * 2 In [4]: b Out[4]: array([ 1., 1., 1., 1., 1.]) In [5]: a *= 2 In [6]: b Out[6]: array([ 2., 2., 2., 2., 2.]) -- Dag _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
