Hi Chris
On Tue, May 24, 2011 at 9:29 AM, Goo Creations <[email protected]> wrote:
> At this point I'm stuck, since I'm not sure how to do the row based
> transform on ownRes.
> Is there anyone out there who knows how to do this?
NumPy's FFT supports an "axis" argument, so you can do
In [29]: own = np.array([[1+0j, 2+0j], [3+0j, 4+0j]])
In [30]: fft_step1 = np.fft.fft(own, axis=0)
In [31]: fft_step2 = np.fft.fft(fft_step1, axis=1)
In [32]: fft_step2
Out[32]:
array([[ 10.+0.j, -2.+0.j],
[ -4.+0.j, 0.+0.j]])
In [33]: np.fft.fft2(own)
Out[33]:
array([[ 10.+0.j, -2.+0.j],
[ -4.+0.j, 0.+0.j]])
Cheers
Stéfan
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