Matthew Brett wrote: > should raise an error. On the other hand, if I make a normal array: > > arr = np.array([1.0, 2.0, 7.0]) > > and then do this: > > arr.visible[2] = False > > then either I should raise an error (it's not a masked array), or, > more magically, construct a mask on the fly.
maybe it's too much Magic, but it seems reasonable to me that for an array without a mask, arr.visible[i] is simply True for all values of i -- no need to create a mask to determine that. does arr[i] = np.IGNORE auto-create a mask if there is not one there already? I think it should. -Chris -- Christopher Barker, Ph.D. Oceanographer Emergency Response Division NOAA/NOS/OR&R (206) 526-6959 voice 7600 Sand Point Way NE (206) 526-6329 fax Seattle, WA 98115 (206) 526-6317 main reception chris.bar...@noaa.gov _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
