Hi, I'm completely new to this list (and fairly new to numpy in general), but I was wondering if you tried multiplying the bool array and the original array.
Try: x=array([[0,1,2],[3,4,5],[6,7,8]]) if rank(x) <= 1 dot(x>=1, x) else (x>=1)*x This will give you a completely numerical array of the same structure, but all numbers less than 1 will be zero fo easy handling. Is this what you're trying to accomplish? -- Derek On Thu, Mar 15, 2012 at 08:35, jonasr <[email protected]> wrote: > > Hello, > > my problem is that i want to remove some small numbers of an 2d array, > for example if i want to sort out all numbers smaller then 1 of an array i > get > > x=[[0,1,2],[3,4,5][6,7,8]] > > c=x>=1 > > In [213]: c > Out[213]: > array([[False, True, True], > [ True, True, True], > [ True, True, True]], dtype=bool) > > In [214]: x[c] > Out[214]: array([1, 2, 3, 4, 5, 6, 7, 8]) > > the problem ist that i now have a 1d array, is there any possibility to > keep the 2d structure ? > > greets jonas > -- > View this message in context: > http://old.nabble.com/Replace-array-values-tp33506446p33506446.html > Sent from the Numpy-discussion mailing list archive at Nabble.com. > > _______________________________________________ > NumPy-Discussion mailing list > [email protected] > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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