There's nothing like that built into numpy, no. I guess you could use reduceat to calculate the total for each span of non-nans and then replace each nan with the negative of that value so that plain cumsum would work, but a loop is going to be easier (and a loop in Cython will be faster).
-n On 23 Oct 2012 18:11, "Cera, Tim" <t...@cerazone.net> wrote: > I have an array that is peppered throughout in random spots with 'nan'. I > would like to use 'cumsum', but I want it to reset the accumulation to 0 > whenever a 'nan' is encountered. Is there a way to do this? Aside from a > loop - which is what I am going to setup here in a moment. > > Kindest regards, > Tim > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion > >
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