If A is very large and B is very small then np.concatenate(A, B) will copy B's data over to A which would take less time than the other way around - is that so?
Does 'memory order' mean that it depends on sufficient contiguous memory being available for B otherwise it will be fragmented or something else? _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion