To rephrase my most pressing question: may np.ones((N,2)).mean(0) and np.ones((2,N)).mean(1) produce different results with the implementation in the current master? If so, I think that would be very much regrettable; and if this is a minority opinion, I do hope that at least this gets documented in a most explicit manner.
On Sun, Jul 27, 2014 at 8:26 PM, Sturla Molden <sturla.mol...@gmail.com> wrote: > Nathaniel Smith <n...@pobox.com> wrote: > > > The problem here is that when summing up the values, the sum gets > > large enough that after rounding, x + 1 = x and the sum stops > > increasing. > > Interesting. That explains why the divide-and-conquer reduction is much > more robust. > > Thanks :) > > > Sturla > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@scipy.org > http://mail.scipy.org/mailman/listinfo/numpy-discussion >
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